https://www.maa.org/programs/students/fun-math

*cheers to MAA! ðŸ™‚*

Nalin Pithwa.

Mathematics demystified

September 30, 2017 – 8:47 pm

September 23, 2017 – 11:08 am

I have a collection of some “random”, yet what I call ‘beautiful” questions in Co-ordinate Geometry. I hope kids preparing for IITJEE Mains or KVPY or ISI Entrance Examination will also like them.

Problem 1:

Given n straight lines and a fixed point O, a straight line is drawn through O meeting lines in the points , , , , and on it a point R is taken such that

Show that the locus of R is a straight line.

Solution 1:

Let equations of the given lines be , , and the point O be the origin .

Then, the equation of the line through O can be written as where is the angle made by the line with the positive direction of x-axis and r is the distance of any point on the line from the origin O.

Let be the distances of the points from O which in turn and , where .

Then, coordinates of R are and of are where .

Since lies on , we can say for

, for

…as given…

Hence, the locus of R is which is a straight line.

Problem 2:

Determine all values of for which the point lies inside the triangle formed by the lines , , .

Solution 2:

Solving equations of the lines two at a time, we get the vertices of the given triangle as: , and .

So, AB is the line , AC is the line and BC is the line

Let be a point inside the triangle ABC. (please do draw it on a sheet of paper, if u want to understand this solution further.) Since A and P lie on the same side of the line , both and must have the same sign.

or which in turn which in turn either or ….call this relation I.

Again, since B and P lie on the same side of the line , and have the same sign.

and , that is, …call this relation II.

Lastly, since C and P lie on the same side of the line , we have and have the same sign.

that is

or ….call this relation III.

Now, relations I, II and III hold simultaneously if or .

Problem 3:

A variable straight line of slope 4 intersects the hyperbola at two points. Find the locus of the point which divides the line segment between these two points in the ratio .

Solution 3:

Let equation of the line be where c is a parameter. It intersects the hyperbola at two points, for which , that is, .

Let and be the roots of the equation. Then, and . If A and B are the points of intersection of the line and the hyperbola, then the coordinates of A are and that of B are .

Let be the point which divides AB in the ratio , then and , that is, …call this equation I.

and ….call this equation II.

Adding I and II, we get , that is,

….call this equation III.

Subtracting II from I, we get

so that the locus of is

More later,

Nalin Pithwa.

September 23, 2017 – 10:32 am

Kids now-a-days need counselling for a choice of career. In my humble opinion, excellence in any field of knowledge/human endeavour gives deep satisfaction as well as a means of livelihood. But, I am a mere mortal, most of my students are bright, ambitious, multi-talented and hard-working. I would like to present to them the views of one of my “idols”, though not a mathematician…

Dr. Shawna Pandya:

Hats off to Dr. Shawna Pandya, belated though from me…:-)

— Nalin Pithwa.

September 22, 2017 – 3:06 am

Problem 1:

The line joining and is produced to the point so that , then find the value of .

Solution 1:

As M divides AB externally in the ratio , we have and which in turn

Problem 2:

If the circumcentre of a triangle lies at the origin and the centroid in the middle point of the line joining the points and , then where does the orthocentre lie?

Solution 2:

From plane geometry, we know that the circumcentre, centroid and orthocentre of a triangle lie on a line. So, the orthocentre of the triangle lies on the line joining the circumcentre and the centroid , that is, , or . That is, the orthocentre lies on this line.

Problem 3:

If a, b, c are unequal and different from 1 such that the points , and are collinear, then which of the following option is true?

a:

b:

c:

d:

Solution 3:

Suppose the given points lie on the line then a, b, c are the roots of the equation :

, or

and , that is,

Eliminating l, m, n, we get

, that is, option (d) is the answer.

Problem 4:

If and are in A.P., with common difference a and b respectively, then on which line does the centre of mean position of the points with lie?

Solution 4:

Note: Centre of Mean Position is .

Let the coordinates of the centre of mean position of the points , be then

and

,

and

, and

, that is, the CM lies on this line.

Problem 5:

The line L has intercepts a and b on the coordinate axes. The coordinate axes are rotated through a fixed angle, keeping the origin fixed. If p and q are the intercepts of the line L on the new axes, then what is the value of ?

Solution 5:

Equation of the line L in the two coordinate systems is , and where are the new coordinate of a point when the axes are rotated through a fixed angle, keeping the origin fixed. As the length of the perpendicular from the origin has not changed.

or . So, the value is zero.

Problem 6:

Let O be the origin, and and are points such that and , then which of the following options is true:

a: P lies either inside the triangle OAB or in the third quadrant

b: P cannot lie inside the triangle OAB

c: P lies inside the triangle OAB

d: P lies in the first quadrant only.

Solution 6:

Since , P either lies in the first quadrant or in the third quadrant. The inequality represents all points below the line . So that and imply that either P lies inside the triangle OAB or in the third quadrant.

Problem 7:

An equation of a line through the point whose distance from the point has the greatest value is :

option i:

option ii:

option iii:

option iv:

Solution 7:

Let the equation of the line through be . If p denotes the length of the perpendicular from on this line, then

, say

then is greatest if and only if s is greatest.

Now,

so that . Also, , if , and

, if

and , if . So s is greatest for . And, thus, the equation of the required line is .

Problem 8:

The points , , Slatex C(4,0)$ and are the vertices of a :

option a: parallelogram

option b: rectangle

option c: rhombus

option d: square.

*Note: more than one option may be right. Please mark all that are right.*

Solution 8:

Mid-point of AC =

Mid-point of BD =

the diagonals AC and BD bisect each other.

ABCD is a parallelogram.

Next, and and since the diagonals are also equal, it is a rectangle.

As and , the adjacent sides are not equal and hence, it is neither a rhombus nor a square.

Problem 9:

Equations and will represent the same line if

option i:

option ii:

option iii:

option iv:

Solution 9:

The two lines will be identical if there exists some real number k, such that

, and , and .

or

or , and

or

That is, or , or .

Next, . Hence, , or .

Problem 10:

The circumcentre of a triangle with vertices , and lies at the origin, where and . Show that it’s orthocentre lies on the line

Solution 10:

As the circumcentre of the triangle is at the origin O, we have , where r is the radius of the circumcircle.

Hence,

Therefore, the coordinates of A are . Similarly, the coordinates of B are and those of C are . Thus, the coordinates of the centroid G of are

.

Now, if is the orthocentre of , then from geometry, the circumcentre, centroid, and the orthocentre of a triangle lie on a line, and the slope of OG equals the slope of OP.

Hence,

because .

Hence, the orthocentre lies on the line

.

Hope this gives an assorted flavour. More stuff later,

Nalin Pithwa.

September 21, 2017 – 2:11 pm

**Mathematicians are like Frenchmen: whatever you tell to them they translate in their own language and forthwith it is something entirely different. — GOETHE.**

ðŸ™‚ ðŸ™‚ ðŸ™‚

September 19, 2017 – 1:56 pm

I.Â **Results regarding points in a plane:**

1a)Â **Distance Formula:**

The distance between two points and is given by . The distance from the origin to the point is .

1b)Â **Section Formula:**

If divides the join of and in the ratio with , then

, and

The positive sign is taken for internal division and the negative sign for external division. TheÂ *mid-pointÂ *of and is which corresponds to internal division, when . Note that for external division .

1c)Â **Centroid of a triangle:**

If is the centroid of the triangle with vertices , and then and

1d)Â **Incentre of a triangle:**

If is the incentre of the triangle with vertices , , and , then

, , a, b and c being the lengths of the sides BC, CA and AB, respectively of the triangle ABC.

1e)Â **Area of triangle:**

ABC with vertices , , and is ,

and is generally denoted by . Note that if one of the vertex is at , then .

*Note:Â *When A, B, and C are taken as vertices of a triangle, it is assumed that they are not collinear.

1f)Â **Condition of collinearity:**

Three points , , and are collinear if and only if

1g)Â **Slope of a line:**

Let and with be any two points. Then, the slope of the line joining A and B is defined as

where is the angle which the line makes with the positive direction of the x-axis, , except at . Which is possible only if and the line is parallel to the y-axis.

1h)Â **Condition for the pointsÂ **, to form an equilateral triangle is

**II) Standard Forms of the Equation of a Line:**

- An equation of a line parallel to the x-axis is and that of the x-axis itself is .
- An equation of a line parallel to the y-axis is and that of the y-axis itself is .
- An equation of a line passing through the origin and (a) making an angle with the positive direction of the x-axis is , and (b) having a slope m is , and (c) passing through the point .
*Slope-intercept form:Â*An equation of a line with slope m and making an intercept c on the y-axis is .*Point-slope form:Â*An equation of a line with slope m and passing through is .*Two-point form:Â*An equation of a line passing through the points and is .*Intercept form:Â*An equation of a line making intercepts a and b on the x-axis and y-axis respectively, is .*Parametric form:Â*An equation of a line passing through a fixed point and making an angle with with with the positive direction of the x-axis is where r is the distance of any point on the line from the point . Note that and .*Normal form:Â*An equation of a line such that the length of the perpendicular from the origin on it is p and the angle which this perpendicular makes with the positive direction of the x-axis is , is .*General form:Â*In general, an equation of a straight line is of the form , where a, b, and c are real numbers and a and b cannot both be zero simultaneously. From this general form of the equation of the line, we can calculate the following: (i) the slope is (ii) the intercept on the x-axis is with and the intercept on the y-axis is with (iii) and and , the positive sign being taken if c is negative and vice-versa (iv) If denotes the length of the perpendicular from on this line, then and (v) the points and lie on the same side of the line if the expressions and have the same sign, and on the opposite side if they have the opposite signs.

**III) Some results for two or more lines:**

- Two lines given by the equations and are
*parallel*(that is, their slopes are equal) if*perpendicular*(that is, the product of their slopes is -1) if*identicalÂ*if*not parallel,Â*then- angle between them at their point of intersection is given by where being the slopes of the two lines.
- the coordinates of their points of intersection are
- An equation of any line through their point of intersection is where is a real number.

- An equation of a line parallel to the line is , and the distance between these lines is
- The three lines , and are
*concurrent*(intersect at a point) if and only if - Equations of theÂ
*bisectors of the anglesÂ*between two intersecting lines and are . Any point on the bisectors is equidistant from the given lines. If is the angle between one of the bisectors and one of the lines such that , that is, , then that bisector bisects the acute angle between the two lines, that is, it is theÂ*acute angle bisectorÂ*of the two lines. The other equation then represents the*obtuse angle**bisectorÂ*between the two lines. - Equations of the lines through and making an angle with the line , are where and where where is the slope of the given line. Note that and and when , .

**IV) Some Useful Points:**

To show that A, B, C, D are the vertices of a

**parallelogram:Â**show that the diagonals AC and BD bisect each other.**rhombus:Â**show that the diagonals AC and BD bisect each other and a pair of adjacent sides, say, AB and BC are equal.**square:Â**show that the diagonals AC and BD are equal and bisect each other, a pair of adjacent sides, say AB and BC are equal.**rectangle:Â**show that the diagonals AC and BD are equal and bisect each other.

**V) Locus of a point:**

To obtain the equation of a set of points satisfying some given condition(s) called locus, proceed as follows:

- Let be any point on the locus.
- Write the given condition involving h and k and simplify. If possible, draw a figure.
- Eliminate the unknowns, if any.
- Replace h by x and k by y and obtain an equation in terms of and the known quantities. This is the required locus.

**VI) Change of Axes:**

**Rotation of Axes:Â**if the axes are rotated through an angle in the anti-clockwise direction keeping the origin fixed, then the coordinates of a point with respect to the new system of coordinates are given by and .**Translation of Axes:Â**the shifting of origin of axes without rotation of axes is calledÂ*translation of axes.Â*If the origin is shifted to the point without rotation of the axes then the coordinates of a point with respect to the new system of coordinates are given by and .

*I hope to present some solved sample problems with solutions soon.*

Nalin Pithwa.

September 18, 2017 – 1:02 am

September 16, 2017 – 5:15 am

Aber das ist English ! ðŸ™‚

**Question 1:**

Find the equation to that tangent to the parabola which is parallel to the straight line . Find also its point of contact.

**Question 2:**

If P, Q and R are three points on the parabola whose coordinates are in geometric progression, prove that the tangents at P and R meet on the ordinate of Q.

**Question 3:**

is a double ordinate of the parabola . Prove that the locus of the point of intersection of the normal at P and straight line through parallel to the axis is the parabola .

**Question 4:**

Show that in a parabola, the length of the focal chord varies inversely as the square of the distance of the vertex of the parabola from the focal chord.

**Question 5:**

Prove that the equation represents a parabola whose axis is parallel to the x-axis.. Find its vertex.

**Question 6:**

If the line touches the parabola , find the length of the latus rectum.

**Question 7a:**

Prove that the circle described on any focal chord of a parabola as the diameter touches the directrix of the parabola.

**Question 7b:**

Show that the locus of the point, such that two of the normals drawn from it to the parabola coincide is .

**Question 7c:**

If the normals at three points A, B and C on the parabola pass through the point and cut the axis of the parabola in P, Q and R so that OP, OQ, OR are in AP, O being the vertex **o**f the parabola, prove that the locus of the point S is .

**Question 8:**

If P, Q and R be three conormal points on the parabola , the normals at which pass through the point T, and S is the focus of the parabola, then prove that

**Question 9:**

The tangents at P and Q to the parabola meet in T and the corresponding normals meet in R. If the locus of T is a straight line parallel to the axis of the parabola, prove that the locus of R is a straight line normal to the parabola.

**Question 10a:**

A variable chord PQ of the parabola is drawn parallel to the line . If the parameters of the points P and Q on the parabola be and , then . Also, show that the locus of the point of intersection of the normals at P and Q is , which is itself a normal to the parabola.

**Question 10b:**

PQ is a chord of the parabola whose right bisector meets the axis in M and the ordinate of the mid-point of PQ meets the axis in L. Show that LM is constant and find LM.

**Question 11:**

Prove that the locus of a point P such that the slopes , , of the three normals drawn to the parabola from P be connected by the relation is .

**Question 12a:**

If the perpendicular drawn from P on the polar of P with respect to the parabola, , prove that the locus of P is the straight line .

**Question 12b:**

Prove that the locus of the poles of the tangent to the parabola w.r.t. the circle is .

**Question 13:**

Tangents are drawn to the parabola at the points P and Q whose inclination to the axis are , . If A be the vertex of the parabola and the circles on AP and AQ as diameters intersect in R and AR be inclined at an angle to the axis, then prove that .

**Question 14:**

Through the vertex O of a parabola chords OP and OQ are drawn at right angles to one another. Prove that for all positions of P, PQ cuts the axis of the parabola at a fixed point. Also, find the locus of the middle point of PQ.

**Question 15a:**

Prove that the area of a triangle inscribed in a parabola is twice the area of the triangle formed by the tangents at the vertices of the triangle.

**Question 15b:**

Normals are drawn to the parabola at points A, B, and C whose parameter are , , respectively. If these normals enclose a triangle PQR, then prove that its area is . Also, prove that .

**Question 16:**

Find the locus of the middle points of the chords of the ellipse which are drawn through the positive end of the minor axis.

**Question 17:**

Prove that the sum of the squares of the perpendiculars on any tangent to the ellipse from the points on the minor axis, each at a distance from the centre, is .

**Question 18:**

If and are two variable points on the ellipse such that (some constant), then prove that the tangent at is parallel to PQ.

**Question 19:**

P is a variable point on the ellipse whose foci are the points , and the eccentricity is e. Prove that the locus of incentre of is an ellipse whose eccentricity is .

**Question 20:**

Consider the family of circles , . If in the first quadrant, the common tangent to a circle of this family and the ellipse meets the coordinate axes at A and B, then find the equation of the locus of the mid-point of AB.

**Question 21:**

Let P be a point on the ellipse , . Let the line parallel to y-axis passing through P meet the circle at the point Q such that P and Q are on the same side of the x-axis. For two positive real numbers, r and s, find the locus of the point R on PQ such that as P varies over the ellipse.

**Question 22:**

If the eccentric angles of points P and Q on the ellipse be and and be the angle between the normals at P and Q, then prove that the eccentricity e is given by .

**Question 23:**

A series of hyperbolas are such that the length of their transverse axis is 2a. Prove that the locus of a point P on each, such that its distance from transverse axis is equal to its distance from an asymptote is the curve:

.

**Question 24:**

A variable line of slope 4 intersects the hyperbola at two points. Find the locus of the point which divides the line segment between these two points in the ratio 1:2.

**Question 25:**

If the tangent at the point on the hyperbola cuts the auxillary circle in points whose coordinates are and , then show that q is harmonic mean of and .

**Question 26:**

Show that the locus of poles with respect to the parabola of the tangents to the hyperbola to the ellipse .

**Question 27:**

The point P on the hyperbola with focus S is such that the tangent at P, the latus rectum through S and one asymptote are concurrent. Prove that SP is parallel to other asymptote.

**Question 28:**

If a triangle is inscribed in a rectangular hyperbola, prove that the orthocentre of the triangle lies on the curve.

**Question 29:**

A series of chords of the hyperbola touch the circle on the line joining the foci as diameter. Show that the locus of the poles of these chords with respect to the hyperbola is .

**Question 30:**

Prove that the chord of the hyperbola which touches the conjugate hyperbola is bisected at the point of contact.

*Cheers,*

Nalin Pithwa.

September 16, 2017 – 3:00 am

**Question 1:**

Find the locus of the point of intersection of tangents to the ellipse , which are at right angles.

**Solution 1:**

Any tangent to the ellipse is …call this equation I.

Equation of the tangent perpendicular to this tangent is …call this Equation II.

The locus of the point of intersection of I and II is obtained by eliminating m between these equations. Squaring and adding we get:

which is a circle with its centre at the centre of the ellipse and radius equal to the length of the line joining the ends of the major and minor axis. This circle is calledÂ * the director circle of the ellipse.Â *ðŸ™‚

**Question 2:**

A tangent to the ellipse meets the ellipse at P and Q. Prove that the tangents at P and Q of the ellipse are at right angles.

**Solution 2:**

Let the tangent at to the ellipse (equation I) meet the ellipse (equation II) at P and Q.

Let the tangents at P and Q to II intersect at the point . Then, PQ is the chord of contact of the point with respect to II and so its equation is ( Equation III).

PQ is also the tangent at to I and so its equation can be written as

(Equation IV)

Comparing III and IV, we get

,

, ,

the locus of is or , which is the director circle of the ellipse II. Hence, the tangents at P and Q to the ellipse II are at right angles (using the previous example). ðŸ™‚

**Question 3:**

Let d be the perpendicular distance from the centre of the ellipse to the tangent drawn at a point P on the ellipse. If and are the two foci of the ellipse, then prove that .

**Solution 3:**

Equation of the tangent at the point on the given ellipse is . Thus,

.

We know that

…call this equation I.

Also, ,

which in turn equals

,

which in turn equals

,

which in turn equals

,

which in turn equals

Now, from I, we get

Also,

which in turn equals

.

Hence, . ðŸ™‚

More later,

Nalin Pithwa.

September 13, 2017 – 9:11 pm

**Question I:**

Given the base of a triangle and the ratio of the tangents of half the base angles, prove that the vertex moves on a hyperbola, whose foci are the extremities of the base.

**Solution I:**

Let the base of the triangle ABC be , and

Then, we get

$\Longrightarrow latex a+(b-c)=K(a-(b-c))$

Since a and K are given constants, is a constant, say . Therefore, we get , that is, . We find that the vertex A moves in such a manner that the difference of its distances from two fixed points B and C, which are the extremities of the base is constant. Hence, it describes a hyperbola whose foci are the extremities of the base. For instance, you will get further insight if you try the following: (in previous blog, basics 4, of coordinate geometry) : Show that the difference of focal distances of any point on a hyperbola is constant and equal to the length of the transverse axis.

**Question 2:**

Show that the angle between the tangents to the ellipse and the circle at their points of intersection is .

**Solution 2:**

For the points of intersection, we have

Consider the point , intersection of the given ellipse and the circle. Equation of the tangent at P to the circle is

Slope of this tangent is . Equation of the tangent at P to the ellipse is and slope of this tangent is . If be the angle between these tangents, then .

Hence, .Â * Note:Â *The angle will be the same at each point of intersection.

**Question 3:**

A straight line is drawn parallel to the conjugate axis of the hyperbola to meet it and the conjugate hyperbola in the points P and Q respectively. Show that the normals at P and Q to the curves meet on the x-axis.

**Solution 3:**

*Conjugate HyperbolaÂ *of the given hyperbola is the hyperbola whose transverse and conjugate axis are respectively the conjugate and transverse axis of the given hyperbola and thus the equation is .

Now, is a point of the given hyperbola and is a point on the conjugate hyperbola. Since P and Q lie on the line parallel to the conjugate axis , of the given hyperbola, , .

Now, equation of the normal at P to the given hyperbola is …call this equation I.

and equation of the normal at Q to the conjugate hyperbola is ….call this equation II.

Eliminating x from I and II, using we get: , which in turn, implies that . Hence, the normals meet on the x-axis.

More later, including homeworks,

Nalin Pithwa.