## A Basket of Eggs — solution

Ref: previous blog article: A Basket of Eggs:

It is related to LCM’s ! 🙂

The LCM of 2, 3, 4, 5, and 6 is 60. We have to find a multiple of 7 that is larger by 1 than a multiple of 60. Now,

$60n+1 = (7 \times 8n) + 4n +1$.

The number $60n+1$ is divisible by 7 if $(4n+1)$ is divisible by 7. The lowest value of n that satisfies this condition is 5.

Therefore, there were 301 eggs in the basket.

-Nalin Pithwa

This site uses Akismet to reduce spam. Learn how your comment data is processed.