A Basket of Eggs — solution

Ref: previous blog article: A Basket of Eggs:

It is related to LCM’s ! 🙂

The LCM of 2, 3, 4, 5, and 6 is 60. We have to find a multiple of 7 that is larger by 1 than a multiple of 60. Now,

60n+1 = (7 \times 8n) + 4n +1.

The number 60n+1 is divisible by 7 if (4n+1) is divisible by 7. The lowest value of n that satisfies this condition is 5.

Therefore, there were 301 eggs in the basket.

-Nalin Pithwa

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